分解因式4(2x^2-x+1)(x^2-2x+3)-(3x^2-3x+4)^2

4(2x^2-x+1)(x^2-2x+3)-(3x^2-3x+4)^2
=4(2x^2-x+1)(x^2-2x+3)-[(2x^2-x+1)+(x^2-2x+3)]^2
=4(2x^2-x+1)(x^2-2x+3)-(2x^2-x+1)^2-(x^2-2x+3)^2-2(2x^2-x+1)(x^2-2x+3)
=-(2x^2-x+1)^2-(x^2-2x+3)^2+2(2x^2-x+1)(x^2-2x+3)
=-[(2x^2-x+1)^2+(x^2-2x+3)^2-2(2x^2-x+1)(x^2-2x+3)
=-[(2x^2-x+1)-(x^2-2x+3)]^2
=-(x^2+x-2)^2
=-(x+2)^2(x-1)^2

虽然晚了点，但您能按下"满意答案＂这个键吗?

分开算
没有简便方法！！！